Question

what volume of 1.25 m hcl reacts with 13.49 g al in the reaction below? 2al + 6hcl → 2alcl₃ + 3h₂ ? l hcl

Explanation:

Step1: Calculate moles of Al

Molar mass of Al is 26.98 g/mol. Moles of Al = mass / molar mass = $13.49\ g \div 26.98\ g/mol$ = $0.5\ mol$.

Step2: Determine moles of HCl from stoichiometry

From the reaction, 2 moles of Al react with 6 moles of HCl. So, moles of HCl = (6/2) × moles of Al = $3 \times 0.5\ mol$ = $1.5\ mol$.

Step3: Calculate volume of HCl solution

Molarity (M) = moles / volume (L). So, volume (L) = moles / M = $1.5\ mol \div 1.25\ M$ = $1.2\ L$.

Answer:

1.2