Question

when an unknown quantity of sulfuric acid dissociates in water, 8.65 kj of heat are released to the surroundings. the volume of the solution does not appreciably change. which description relates the signs for heat and work for the dissociation of sulfuric acid? q = -, w = 0; q = -, w = -; q = +, w = 0

Explanation:

1. Understanding \( q \) (heat): When a system (sulfuric acid dissolving) releases heat to the surroundings, the heat change for the system (\( q \)) is negative. This is because \( q \) is defined as positive when the system absorbs heat and negative when it releases heat.
2. Understanding \( w \) (work): Work done by or on a system is related to volume changes (pressure - volume work, \( w=-P\Delta V \)). The problem states the volume of the solution does not appreciably change, so \( \Delta V = 0 \). Substituting into the work formula \( w=-P\Delta V \), we get \( w = 0 \) (since \( \Delta V = 0 \)).

Answer:

A. \( \boldsymbol{q = -, w = 0} \)