Question

write the chemical symbols for three different atoms or atomic anions with 36 electrons.

Explanation:

Step1: Recall atomic number and electron - count relationship

For a neutral atom, the number of electrons is equal to the atomic number (Z). For an anion, the number of electrons = Z + charge.

Step2: Identify neutral atom with 36 electrons

The neutral atom with 36 electrons has an atomic number of 36, which is Krypton. Its symbol is Kr.

Step3: Identify an anion with 36 electrons

Bromine (Br) has an atomic number of 35. When it gains one electron to form a bromide ion ($Br^-$), the number of electrons is 35 + 1=36.

Step4: Identify another anion with 36 electrons

Selenium (Se) has an atomic number of 34. When it gains two electrons to form a selenide ion ($Se^{2 - }$), the number of electrons is 34+2 = 36.

Answer:

Kr, $Br^-$, $Se^{2 - }$