Question

1. _zn + _hcl → _zncl₂ + _h₂

balanced equation: ___________
molar mass of reactants (g/mol): ________
molar mass of products (g/mol): ________

1. _na₂co₃ + _hcl → _nacl + _h₂o + _co₂

balanced equation: ___________
molar mass of reactants (g/mol): ________
molar mass of products (g/mol): ________

1. _ch₄ + _o₂ → _co₂ + _h₂o

balanced equation: ___________
molar mass of reactants (g/mol): ________
molar mass of products (g/mol): ________

1. _c₃h₈ + _o₂ → _co₂ + _h₂o

balanced equation: ___________
molar mass of reactants (g/mol): ________
molar mass of products (g/mol): ________

Explanation:

Step1: Balance equation 7

Count atoms, adjust coefficients.
$\text{Zn} + 2\text{HCl}
ightarrow \text{ZnCl}_2 + \text{H}_2$

Step2: Calculate molar masses (7)

Use atomic weights: Zn=65.38, H=1.008, Cl=35.45.
Reactants: $\text{Zn}: 65.38\ \text{g/mol}$, $\text{HCl}: 1.008 + 35.45 = 36.458\ \text{g/mol}$
Products: $\text{ZnCl}_2: 65.38 + 2\times35.45 = 136.28\ \text{g/mol}$, $\text{H}_2: 2\times1.008 = 2.016\ \text{g/mol}$

Step3: Balance equation 8

Count atoms, adjust coefficients.
$\text{Na}_2\text{CO}_3 + 2\text{HCl}
ightarrow 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2$

Step4: Calculate molar masses (8)

Use atomic weights: Na=22.99, C=12.01, O=16.00.
Reactants: $\text{Na}_2\text{CO}_3: 2\times22.99 + 12.01 + 3\times16.00 = 105.99\ \text{g/mol}$, $\text{HCl}: 36.458\ \text{g/mol}$
Products: $\text{NaCl}: 22.99 + 35.45 = 58.44\ \text{g/mol}$, $\text{H}_2\text{O}: 2\times1.008 + 16.00 = 18.016\ \text{g/mol}$, $\text{CO}_2: 12.01 + 2\times16.00 = 44.01\ \text{g/mol}$

Step5: Balance equation 9

Count atoms, adjust coefficients.
$\text{CH}_4 + 2\text{O}_2
ightarrow \text{CO}_2 + 2\text{H}_2\text{O}$

Step6: Calculate molar masses (9)

Use atomic weights: O=16.00.
Reactants: $\text{CH}_4: 12.01 + 4\times1.008 = 16.042\ \text{g/mol}$, $\text{O}_2: 2\times16.00 = 32.00\ \text{g/mol}$
Products: $\text{CO}_2: 44.01\ \text{g/mol}$, $\text{H}_2\text{O}: 18.016\ \text{g/mol}$

Step7: Balance equation 10

Count atoms, adjust coefficients.
$\text{C}_3\text{H}_8 + 5\text{O}_2
ightarrow 3\text{CO}_2 + 4\text{H}_2\text{O}$

Step8: Calculate molar masses (10)

Use atomic weights: C=12.01, H=1.008.
Reactants: $\text{C}_3\text{H}_8: 3\times12.01 + 8\times1.008 = 44.094\ \text{g/mol}$, $\text{O}_2: 32.00\ \text{g/mol}$
Products: $\text{CO}_2: 44.01\ \text{g/mol}$, $\text{H}_2\text{O}: 18.016\ \text{g/mol}$

Answer:

Problem 7

Balanced Equation: $\boldsymbol{\text{Zn} + 2\text{HCl}
ightarrow \text{ZnCl}_2 + \text{H}_2}$
Molar Mass of Reactants (g/mol): Zn: 65.38, HCl: 36.46
Molar Mass of Products (g/mol): $\text{ZnCl}_2$: 136.28, $\text{H}_2$: 2.02

Problem 8

Balanced Equation: $\boldsymbol{\text{Na}_2\text{CO}_3 + 2\text{HCl}
ightarrow 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2}$
Molar Mass of Reactants (g/mol): $\text{Na}_2\text{CO}_3$: 105.99, HCl: 36.46
Molar Mass of Products (g/mol): NaCl: 58.44, $\text{H}_2\text{O}$: 18.02, $\text{CO}_2$: 44.01

Problem 9

Balanced Equation: $\boldsymbol{\text{CH}_4 + 2\text{O}_2
ightarrow \text{CO}_2 + 2\text{H}_2\text{O}}$
Molar Mass of Reactants (g/mol): $\text{CH}_4$: 16.04, $\text{O}_2$: 32.00
Molar Mass of Products (g/mol): $\text{CO}_2$: 44.01, $\text{H}_2\text{O}$: 18.02

Problem 10

Balanced Equation: $\boldsymbol{\text{C}_3\text{H}_8 + 5\text{O}_2
ightarrow 3\text{CO}_2 + 4\text{H}_2\text{O}}$
Molar Mass of Reactants (g/mol): $\text{C}_3\text{H}_8$: 44.09, $\text{O}_2$: 32.00
Molar Mass of Products (g/mol): $\text{CO}_2$: 44.01, $\text{H}_2\text{O}$: 18.02