Question

1. a heterozygous tall, heterozygous green-flowered plant is crossed with a homozygous short, heterozygous green-flowered plant. what will be the possible genotypes and phenotypes of the offspring? show your work as a punnett square and write your answers as a phenotypic ratio.

Explanation:

Step1: Define parent genotypes

Let \(T\) = tall (dominant), \(t\) = short (recessive); \(G\) = green flower (dominant), \(g\) = non-green flower (recessive).
Parent 1 (heterozygous tall, heterozygous green): \(TtGg\)
Parent 2 (homozygous short, heterozygous green): \(ttGg\)
Gametes of Parent 1: \(TG, Tg, tG, tg\)
Gametes of Parent 2: \(tG, tg, tG, tg\)

Step2: Build correct Punnett Square

	\(TG\)	\(Tg\)	\(tG\)	\(tg\)
\(tg\)	\(TtGg\)	\(Ttgg\)	\(ttGg\)	\(ttgg\)
\(tG\)	\(TtGG\)	\(TtGg\)	\(ttGG\)	\(ttGg\)
\(tg\)	\(TtGg\)	\(Ttgg\)	\(ttGg\)	\(ttgg\)

Step3: Classify phenotypes

• Tall, green flower: \(TtGG, TtGg\) (count = 6)
• Tall, non-green flower: \(Ttgg\) (count = 2)
• Short, green flower: \(ttGG, ttGg\) (count = 6)
• Short, non-green flower: \(ttgg\) (count = 2)

Step4: Simplify phenotypic ratio

Divide all counts by 2 to get the simplest whole-number ratio.

Answer:

Phenotypic ratio: 3 Tall, green-flowered : 1 Tall, non-green-flowered : 3 Short, green-flowered : 1 Short, non-green-flowered (or 3:1:3:1)