Question

2c₄h₁₀ + 13o₂ → 8co₂ + 10h₂o
the reaction uses up 16.8 g c₄h₁₀ from
the original 20.0 g c₄h₁₀. what mass of
excess c₄h₁₀ remains at the completion
of the reaction?
? g c₄h₁₀

Explanation:

Step1: Identify given values

Original mass of \( C_4H_{10} = 20.0 \, \text{g} \), Mass of \( C_4H_{10} \) used = \( 16.8 \, \text{g} \)

Step2: Calculate excess mass

Excess mass = Original mass - Mass used
\( = 20.0 - 16.8 \)
\( = 3.2 \)

Answer:

\( 3.2 \)