Question

for the following reactions, recall the concepts for balancing equations. then, for each chemical formula, count the number of atoms for each element and write them below each formula.

part a

$$6co_2 + 6h_2o \ ightarrow c_6h_{12}o_6 + 6o_2$$

reactants (left side)		products (right side)
o: ______	o: ______	h: ______
		o: ______
total: ______		total: ______

does this equation follow the law of conservation of matter? ______

part b

$$c_7h_{16} + o_2 \ ightarrow co_2 + h_2o$$

reactants (left side)		products (right side)
h: ______		o: ______	o: ______
total: ______		total: ______

does this equation follow the law of conservation of matter? ______

Explanation:

Step1: Count reactant atoms (a)

For $\boldsymbol{6CO_2}$:

C: $6 \times 1 = 6$; O: $6 \times 2 = 12$

For $\boldsymbol{6H_2O}$:

H: $6 \times 2 = 12$; O: $6 \times 1 = 6$

Reactant totals:

C: 6; H: 12; O: $12 + 6 = 18$
Total atoms: $6 + 12 + 18 = 36$

Step2: Count product atoms (a)

For $\boldsymbol{C_6H_{12}O_6}$:

C: 6; H: 12; O: 6

For $\boldsymbol{6O_2}$:

O: $6 \times 2 = 12$

Product totals:

C: 6; H: 12; O: $6 + 12 = 18$
Total atoms: $6 + 12 + 18 = 36$

Step3: Verify Law (a)

Reactant total = Product total, so the law holds.

Step4: Count reactant atoms (b)

For $\boldsymbol{C_7H_{16}}$:

C: 7; H: 16

For $\boldsymbol{O_2}$:

O: 2

Reactant totals:

C:7; H:16; O:2
Total atoms: $7 + 16 + 2 = 25$

Step5: Count product atoms (b)

For $\boldsymbol{CO_2}$:

C:1; O:2

For $\boldsymbol{H_2O}$:

H:2; O:1

Product totals:

C:1; H:2; O: $2 + 1 = 3$
Total atoms: $1 + 2 + 3 = 6$

Step6: Verify Law (b)

Reactant total ≠ Product total, so the law does not hold.

Answer:

Part a:

Reactants				Products
$\boldsymbol{C_6H_{12}O_6}$	C: 6	H: 12	O: 6	$\boldsymbol{6O_2}$	O: 12
Total:	36			Total:	36
Does this equation follow the Law of Conservation of Matter?	Yes

Part b:

Reactants				Products
$\boldsymbol{CO_2}$	C: 1	O: 2	$\boldsymbol{H_2O}$	H: 2	O: 1
Total:	25			Total:	6
Does this equation follow the Law of Conservation of Matter?	No