Question

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Explanation:

Step1: Recall energy formula

The energy of a photon is $E = hf$, where $h=6.626\times10^{-34}\ \text{J·s}$ (Planck's constant), and $f$ is frequency.

Step2: Calculate for 602 nm LED

Substitute $f=4.98\times10^{14}\ \text{Hz}$
$E = 6.626\times10^{-34} \times 4.98\times10^{14}$
$E \approx 3.30\times10^{-19}\ \text{J}$

Step3: Calculate for 640 nm LED

Substitute $f=4.681\times10^{14}\ \text{Hz}$
$E = 6.626\times10^{-34} \times 4.681\times10^{14}$
$E \approx 3.10\times10^{-19}\ \text{J}$

Answer:

LED Wavelength (nm)	Converted Energy to light each LED (J)
640	$3.10\times10^{-19}$