Question

select the correct answer.
robert is a 15 - year - old boy. his recommended dietary intake for vitamin b12, c, and e is 2.4 μg/day, 75 mg/day, and 15 mg/day, respe
eats a salmon fillet with one cup boiled green beans and half a cup of fresh sliced strawberries for lunch. if the nutrient values of his me
components are as shown below, for which vitamins did robert meet at least 75% of his recommended daily allowance?

	vitamin b12	vitamin c	vitamin e
boiled green beans (1 cup)	0.0 μg	12.1 mg	0.57 mg
strawberries, sliced (1/2 cup)	0.0 μg	49.0 mg	0.42 mg

a. vitamin b12, vitamin c, and vitamin e
b. vitamin b12 and vitamin c only
c. vitamin b12 and vitamin e only
d. vitamin c and vitamin e only
e. vitamin b12 only

Explanation:

Step1: Calculate total intake for each vitamin

• Vitamin B12: From salmon fillet, intake is \( 5.87\ \mu g \) (other foods have 0).
• Vitamin C: Sum of green beans (\( 12.1\ mg \)) and strawberries (\( 49.0\ mg \)): \( 12.1 + 49.0 = 61.1\ mg \).
• Vitamin E: Sum of salmon (\( 0.60\ mg \)), green beans (\( 0.57\ mg \)), and strawberries (\( 0.42\ mg \)): \( 0.60 + 0.57 + 0.42 = 1.59\ mg \).

Step2: Calculate 75% of recommended intake for each vitamin

• Vitamin B12: \( 0.75\times2.4 = 1.8\ \mu g \).
• Vitamin C: \( 0.75\times75 = 56.25\ mg \).
• Vitamin E: \( 0.75\times15 = 11.25\ mg \).

Step3: Compare total intake with 75% of recommended

• Vitamin B12: \( 5.87\ \mu g \geq 1.8\ \mu g \) (meets).
• Vitamin C: \( 61.1\ mg \geq 56.25\ mg \) (meets).
• Vitamin E: \( 1.59\ mg < 11.25\ mg \) (does not meet).

Answer:

B. vitamin B12 and vitamin C only