Question

this velocity-time graph depicts the motion of an object. use the graph to determine the displacement (in meters) of the object during the entire 5.0 seconds. enter your answer accurate to the second decimal place.

Explanation:

Step1: Identify graph shape (trapezoid)

The velocity-time graph is a trapezoid with two parallel sides (initial velocity $v_0=5.0\ \text{m/s}$, final velocity $v_f=15.0\ \text{m/s}$) and base $t=5.0\ \text{s}$.

Step2: Use trapezoid area formula

Displacement = area of trapezoid: $\text{Displacement} = \frac{1}{2} \times (v_0 + v_f) \times t$

Step3: Substitute values and calculate

$\text{Displacement} = \frac{1}{2} \times (5.0 + 15.0) \times 5.0 = \frac{1}{2} \times 20.0 \times 5.0 = 50.00$

Answer:

50.00