Question

bf₃ + __li₂so₃ → b₂(so₃)₃ + __lif
na₃po₄ + __hcl → nacl + __h₃po₄

Explanation:

Step1: Balance first reaction (B and F)

Start with balancing boron and fluorine.

$$2\text{BF}_3 + \text{Li}_2\text{SO}_3 ightarrow \text{B}_2(\text{SO}_3)_3 + 6\text{LiF}$$

Step2: Balance sulfur and lithium

Adjust coefficient for $\text{Li}_2\text{SO}_3$ to balance S and Li.

$$2\text{BF}_3 + 3\text{Li}_2\text{SO}_3 ightarrow \text{B}_2(\text{SO}_3)_3 + 6\text{LiF}$$

Step3: Verify first reaction

Check all atom counts: B=2, F=6, Li=6, S=3, O=9 on both sides.

Step4: Balance second reaction (Na and Cl)

Confirm Na and Cl are balanced, check remaining atoms.

$$\text{Na}_3\text{PO}_4 + 3\text{HCl} ightarrow 3\text{NaCl} + \text{H}_3\text{PO}_4$$

Step5: Verify second reaction

Check all atom counts: Na=3, P=1, O=4, H=3, Cl=3 on both sides.

Answer:

1. $2\text{BF}_3 + 3\text{Li}_2\text{SO}_3

ightarrow \text{B}_2(\text{SO}_3)_3 + 6\text{LiF}$

1. $\text{Na}_3\text{PO}_4 + 3\text{HCl}

ightarrow 3\text{NaCl} + \text{H}_3\text{PO}_4$

Filled coefficients: 2, 3, 1, 6 (for first reaction); 1, 3, 3, 1 (for second reaction)