Question

question 14 (1 point)
the compound above is classified as a(n)
a) aldehyde
b) carboxylic acid
c) ketone
d) alkene
e) alkane

Explanation:

The given compound has the structure \( \text{H}_3\text{C}-\text{CH}=\text{O} \) (acetaldehyde). Aldehydes have the functional group \( -\text{CHO} \) (carbonyl group with one hydrogen and one carbon attached). Let's analyze other options:

• Carboxylic acids have \( -\text{COOH} \), not present here.
• Ketones have \( \text{C}=\text{O} \) with two carbon groups attached (no hydrogen on the carbonyl carbon), but here the carbonyl carbon is attached to a hydrogen (from \( -\text{CHO} \)) and a methyl group, so it's an aldehyde.
• Alkenes have \( \text{C}=\text{C} \) (not \( \text{C}=\text{O} \)), alkanes have single bonds only (no double bonds), so d and e are out.
• Ketone (c) requires two carbon groups on the carbonyl carbon, which is not the case here (one group is H, one is methyl), so it's an aldehyde.

Answer:

a) aldehyde